prove that tan 48.tan 16.tan 42.tan 74=1
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We know that Cot(90 -∅) = Tan∅.
So,
tan48. tan16. tan42. tan74
= tan48. tan16. Cot(90-42). cot(90-74)
= tan48. tan16. cot48. cot16
= 1
.......... HENCE PROVED
.... ( USING COT∅. TAN∅ = 1)
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Answered by
3
Answer:
We know that Cot(90 -∅) = Tan∅.
So,
tan48. tan16. tan42. tan74
= tan48. tan16. Cot(90-42). cot(90-74)
= tan48. tan16. cot48. cot16
= 1
.......... HENCE PROVED
.... ( USING COT∅. TAN∅ = 1)
______❗❗❗❗❗❗❗______
HOPE IT WILL HELP YOU....
PLEASE MARK MY ANSWER AS BRAINLIEST.
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