Prove that tan A + sec A -1 / tan A -sec A +1 ==) sin A +1 / cos A
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Step-by-step explanation:
tanA+secA-1/tanA-secA+1
=(tanA+secA)-(sec²A-tan²A)/(tanA-secA+1)
=(secA+tanA)-(secA-tanA)(secA+tanA)/(tanA-secA+1)
=(secA+tanA)(1-secA+tanA)/(tanA-secA+1)
=secA+tanA
=1+sinA/cosA
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