Question

prove that
tan A -sin A/sin³A= secA/1+cosA​

Answer 1

Answer:

SUBAH SUBAH DIMAAG KA BSDA MAT KAR

Step-by-step explanation:

L.H.S. = x2 – y2

= (p sec θ + q tan θ)2 – (p tan θ + q sec θ)2

= p2 sec θ + q2 tan2 θ + 2 pq sec 2 tan 2 -(p2 tan2 θ + q2 sec2 θ + 2pq sec θ tan θ)

= p2 sec θ + 2 tan2 θ + 2pq sec θ tan θ – p2 tan2 θ – q2 sec θ – 2pq sec θ tan θ

= p2(sec2 θ – tan2 θ) – q2(sec?2 θ – tan2 θ) =

= p2 – q2 …[sec2 θ – tan2 θ = 1

= R.H.S.hii

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Answer 2

Answer:

should find terms

and solve with tht formula

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