Question

Prove that: (tan A + sin A) / (tan A – sin A) = (sec A + 1) / (sec A – 1)

Answer 1

Answer:

Step-by-step explanation:

Given ,

LHS =\frac{tanA+sinA}{tanA-sinA}

= \frac{(\frac{sinA}{cosA})+1}{(\frac{sinA}{cosA})-1}

Take sinA common ,we get

=\frac{sinA(\frac{1}{cosA}+1)}{sinA(\frac{1}{cosA}-1)}

After cancellation of SinA , we get

= \frac{secA+1}{secA-1}

/* 1/cosA = secA */

= RHS