Prove that tan inverse x +tan inverse y=tan inverse x+y by 1-xy
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Tan⁻¹x + Tan⁻¹y = Tan⁻¹( (x + y) /( 1 - xy))
Step-by-step explanation:
To be Proved
Tan⁻¹x + Tan⁻¹y = Tan⁻¹((x + y)/(1 - xy) )
Let say
Tan⁻¹x + Tan⁻¹y = M
Taking Tan both sides
TanM = Tan (Tan⁻¹x + Tan⁻¹y )
Tan(A + B) = (TanA + TanB)/(1 - TanATanB)
A = Tan⁻¹x & B =Tan⁻¹y
=> TanM = (Tan(Tan⁻¹x) + Tan( Tan⁻¹y) )/( 1 - Tan(Tan⁻¹x)Tan(Tan⁻¹y))
=> TanM = (x + y) /( 1 - xy)
=> M = Tan⁻¹( (x + y) /( 1 - xy))
M = Tan⁻¹x + Tan⁻¹y
=> Tan⁻¹x + Tan⁻¹y = Tan⁻¹( (x + y) /( 1 - xy))
QED
Proved
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