Question

Prove that tan’o-sin’e = tan’e.sin’o

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Answer 1

Answer:

$\huge{\boxed{\mathcal\purple{♡}{\blue{answer}\purple{♡}}}}$

Step-by-step explanation:

sinθ+cosθ=

3

=(sinθ+cosθ)

2

=3

=sin

2

θ+cos

2

θ+2sinθcosθ=3

⇒2sinθcosθ=2

⇒sinθcosθ=1

⇒sinθcosθ=sin

2

θ+cos

2

θ

⇒1=

sinθcosθ

sin

2

θ+cos

2

θ

⇒tanθ+cotθ=

Thanks i hope its help u ❤✔