Question

prove that :tan (pi/4+A) - tan (pi/4-A) =2tan2A

answer fast..

Answer 1

Here's Ur answer,

➡tan (π/4+A)=[(1+tan A)/(1- tan A]

tan(π/4-A)=[(1-tan A)/((1+tan A)]

➡> tan (π/4+A)-tan (π/4-A)

= {(1+ tan A)^2-(1- tan A)^2}/(1-tan ^2 A)

=4 tan A/(1- tan ^2 A)

=2(2 tan A/(1- tan ^2 A)

✔✔= 2 tan 2A✔✔

Hope it helps
✌✌

Answer 2

Answer:

Step-by-step explanation:tan (π/4+A)=[(1+tan A)/(1- tan A]

tan(π/4-A)=[(1-tan A)/((1+tan A)]

➡> tan (π/4+A)-tan (π/4-A)

= {(1+ tan A)^2-(1- tan A)^2}/(1-tan ^2 A)

=4 tan A/(1- tan ^2 A)

=2(2 tan A/(1- tan ^2 A)

= 2 tan 2A=R.H.S