Prove that tanΘ+secΘ-1/ tanΘ-secΘ+1 = 1+sinΘ/cosΘ
Pls explain each step
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Step-by-step explanation:
tanø+secø-1/tanø-secø+1
=secø+tanø-(sec²ø-tan²ø)/tanø-secø+1
=(secø+tanø)(1-secø+tanø)/(tanø-secø+1)
=secø+tanø
=1+sinø/cosø
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