prove that tan θ / sec θ - 1 + tan θ / sec θ +1 = cosec θ
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Step-by-step explanation:
let theta be A
LHS
tanA/(secA-1)+tanA(secA+1)
={tanA(secA+1)+tanA(secA-1)}/secA^2-1
={tanA*secA+tanA-tanA+secA*tanA}/tanA^2
( as secA^2-1=tanA^2)
=2(secA*tanA)/tanA^2
=2secA/tanA
=(2/cosA)*(cosA/sinA)
=2/sinA
=2cosecA=RHS
hey mate pls check once again your right hand side pls
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Ansh123721:
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if tan θ = p/q show that p sin θ - q cos θ / p sin θ + q cos θ = (p^2-q^2/p^2+q^2)^2
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