prove that tan/sin=cos/1-sin^2
Answers
Answered by
0
tan/sin = cos/(1 - sin^2)
RHS = cos/(1 - sin^2)
= cos/cos^2. [since sin^2 + cos^2 =1]
= 1/cos
LHS = tan/sin
= (sin/cos)/ sin [ since, tan = sin/cos]
= sin / (cos×sin)
= 1/cos
Since, LHS = RHS
HENCE PROVED..
HOPE I HELPED
RHS = cos/(1 - sin^2)
= cos/cos^2. [since sin^2 + cos^2 =1]
= 1/cos
LHS = tan/sin
= (sin/cos)/ sin [ since, tan = sin/cos]
= sin / (cos×sin)
= 1/cos
Since, LHS = RHS
HENCE PROVED..
HOPE I HELPED
Anonymous:
sin /(cos*sin)=1/cos..how?
i know sin^2+cos^2=1 but...1-sin^2=cos??..how?
just explain that cos*sin thing please..
Similar questions