prove that tan square A minus tan square B is equals to sin square A minus sin square b by cos square a into to cos square B
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tan²A - tan²B = sin²A - sin²B ÷ cos² A * cos²B
LHS.,
tan²A - tan²B
⇒ sin²A/cos²A - sin²B/cos²B
⇒ cos²B.sin²A - cos²A.sin²B / cos²A.cos²B
⇒ (1-sin²B).sin²A - (1-sin²A).sin²B / cos²A.cos²B
⇒ sin²A - sin²A.sin²B - sin²B + sin²A.sin²B / cos²A.cos²B
⇒ sin²A - sin²B / cos²A.cos²B
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