Prove that tan square a+tan power 4 a=sec power 4 a- sec square a
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Answer:
L.H.S=R.H.S
Step-by-step explanation:
tan^2A+tan^4A=sec^4-sec^2A
common tan^2A from L.H.S and sec^2A from R.H.S
tan^2A(1+tan^2A)=sec^2A(sec^2A-1)
using identities..
tan^2A×sec^2A= sec^2A×tan^2A
or we can write this statement
tan^2A×sec^2A=tan^2A×sec^2A
proved
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