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Prove that (tan theta + 1/cos theta)²+( tan theta - 1/cos theta)²=2 (1+ sin² theta)/(1- cos ² theta)
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Answer:
LHS = (tan + sec)^2 + (tan - sec)^2=
tan^2 + sec^2 +2tan.sec + tan^2 + sec^2 - 2tan.sec = 2(tan^2 + sec^2)
=2(sin^2+1/cos^2)
=2(sin^2 + 1)/cos^2= 2(1+sin^2)/(1-sin^2) = RHS
put theta in all cases
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