Prove that
Tan theta + cot theta + 2 = sec square theta. Cosec square theta
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Step-by-step explanation:
Solution :
- i think that u have made a little mistake in wrting the question.... the question should be right is this way
- prove that tan2 theta+cot2 theta + 1 = 2 cosec2 theta* sec square theta?
- Now by solving according to right ques:
- Taking L.H.S:
- as tan theta = sin theta divided by cos theta and cot theta is inverse of tan theta
- by breaking tan square and cot square theta into their respective formulas
- sin2 theta divided by cos2 theta + cos2 theta divided by sin2 theta
- Now by taking L.C.M
- sin2 theta + cos2 theta +1 1+1 as sin2 theta + cos2 theta= 1
- ----------------------------- = ---------------
- (cos2 theta) (sin2 theta) (cos2 theta) ( sin2theta)
- 2
- ----- ---------
- (cos2 theta) ( sin2teta)
- as sec2theta = 1 and cosec2theta = 1
- ------ ----------
- cos2theta sin2theta
- so 2 ( 1 divided by cos2theta) = 2 sec square theta
- and 2 ( 1 divided by sin2 theta ) = 2 cosec square theta
- L.H.S = R.H.S
- Hence prooved...
Answered by
1
Answer:
I have answered below for the following question :
tan²θ+ cot²θ + 2 = sec²θ x cosec²θ
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