Prove that tan ( x + y ) = tanx + tany ÷ 1-tanx tany
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It is a trignometrical identity, there is nothing there to solve. The identity is arrived at by simplifying the identities in sin(x+y)/cos(x+y)
= sinxcosy+cosxsiny/cosxcosy−sinxsiny.
Divide the numerator as well as the denominator by cos x cosy to get
tanx+tany/1−tanxtany
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CoolestCat015:
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