Math, asked by rachanajethwa29, 6 months ago

Prove that tan3ø-1/tanø-1 = sec2ø+tanø

Answers

Answered by sandy1816

3

Answer:

(tan³ø-1)/(tanø-1)

=(tanø-1)(tan²ø+tanø+1)/(tanø-1)

=tan²ø+1+tanø

=sec²ø+tanø

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