Question

prove that tan63°.tan27°=1​

Answer 1

Hope it will help you. . . . . . . . .

Answer 2

Hi!

tan 63° × tan 27° = 1

Solving L.H.S.

We know that,

tanΘ = cot ( 90°-Θ)

So,

tan (90-63) × tan 27°

cot 27° × tan 27°

We also know that,

cotΘ = 1/tanΘ

So,

1/tan 27° × tan 27°   ( Here, tan 27° will be canceled out )

1. ( R.H.S.)

Hence proved.