Prove that, tan70 =tan20+2tan50
2 . Prove that,
(sinX)3 × sin3X +(cosX)3 × cos3X =(cos2X)3
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Answer:
tan70=tan(20+50)
tan70 = (tan20+tan50)/(1-tan20tan50)
tan70-tan20tan50tan70 = tan20+tan50
And, [ tan70tan20 = tan70cot70 = 1 ]
so,
tan70-tan50 = tan20+tan50
tan70 = tan20+2tan50 ( proved)
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