Question

prove that tanA(1+sec^2A)=tan2A​

Answer 1

tanA(1+sec2A)=tan2A

tanA(1+1/cos2A)

tanA[1+(1+tan²A)/1-tan²A]

tanA(1-tan²A+1+tan²A)/1-tan²A

tanA(2)/1-tan²A

2tanA/1-tan²A

tan2A

I am sure this is your answer