prove that (tantheta+2)(2tantheta+1)=5tantheta+2sec²theta
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Step-by-step explanation:
( tanx+2)(2tanx+1)
= 2tan²x+ tanx + 4tanx + 2
= 2(tan²+1) + 5tanx
= 2sec²x + 5tanx { tan²x+1= sec²x}
I just replaced theta by x, for convenience to type..... please write the variable in the question
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