Question

prove that
$2 \sqrt{3 - 1}$
is an irrational number​

Answer 1

$\mathfrak{The\:Answer\:is}$

To prove :

$2 \sqrt{3 - 1}$

is an irrational no.

Proof :

$2 \sqrt{3 - 1}$

$= 2 \sqrt{2}$

$= 2 \times 2.23606798$

$= 4.47213596$

which is an irrational no.

Hence proved.

$\boxed{Hope\:This\:Helps}$

Answer 2

Answer:

2root 3-1

=2root 2

Its value is contain decimals so its a rational no.