prove that
is an irrational no.
Anonymous:
Irrational no
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Let it be a rational number.
5 - 3/7 √3 = a/b
=> -3/7 √3 = a/b - 5
=> 3/7 √3 = (5b-a) /b
√3 = 7( 5b-a) /3b
It seems that √3 is rational.
So, our assumption get wrong because √3 is irrational number so 5-3/7√3 is irrational.
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