Question

prove that
$6 \sqrt{2}$
is irrational


​

Answer 1

Answer:

Let us assume that 6+√2 is rational.

That is , we can find coprimes a and b (b≠0) such that

Since , a and b are integers , is rational ,and so √2 is rational.

But this contradicts the fact that √2 is irrational.

So, we conclude that 6+√2 is irrational.

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⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀-ThesnowyPrince

Answer 2

Step-by-step explanation:

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let it be rational

so 6+√2= a/b

\sqrt{2} = \frac{a}{b} - 6

\sqrt{2} = \frac{a - 6b}{b}

And now as we know that √2 is irrational

•°• irrational ≠ rational

HENCE WE CAN SAY THAT

6+√2 is irrational.....❤