Question

prove that
$9x^{2} + 30x + 28$
hv no zero​

Answer 1

Step-by-step explanation:

9x^2+30x+28

a=9,b=30,c=28

b^2-4ac=(30)^2-4(9)(28)

=900-1008=-108

so zeroes are not exist

Answer 2

Answer:

Step-by-step explanation:

b^2-4ac < 0

30^2-4*28*9 < 0

900-1008 < 0

-108 < 0

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