Question

prove that
$\binom{1}{ \sqrt{2} }$
is irrational​

Answer 1

Answer:

We have to prove that 1/√2 is irrational

Let us assume the opposite

i.e, 1/√2 is rational

Hence, 1/√2 can be written in the form a/b.

Where a and b ( b is not equals to 0) are co-prime.

And it is proved that 1/√2 is irrational

Explanation:

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Answer 2

Answer:

Let's suppose √2 is a rational number. Then we can write it √2 = a/b where a, b are whole numbers, b not zero. We additionally assume that this a/b is simplified to lowest terms, since that can obviously be done with any fraction.