Question

prove that
$\binom{1}{ \sqrt{3} ?}$
is an irrational

Answer 1

THERE IS YOURS SOLUTION

So, 1/√3 is irrational.

HOPE IT HELPS

Answer 2

Hi there

Your answer is :-

$\frac{1}{\sqrt3}$

$\frac{1}{\sqrt3}\times \frac{\sqrt3}{\sqrt3}$

$\frac{\sqrt3}{3}$

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Let 1/√3 be rational number

1/√3=p

Now,

√3=q/p

√3 is irrational number, where q/p is rational
Rational number is never equal to irrational number

Hence our contradiction was wrong
1/√3 is a irrational number
hence proved!


Thank You