Question

Prove that :-
$cot^{-1 } \frac{pq+1}{p-q} + cot^{-1} \frac{qr +1}{q - r} + cot^{-1} \frac{rp + 1}{r - p} = 0$
.......

Answer 1

★ INVERSE TRIGONOMETRIC FUNCTIONS ★

The equivalent system will reduce to :

Tan ^-1 ( p - q / pq +1 ) + Tan^-1 ( q - r / qr + 1 ) + Tan ^ -1 ( r - p / rp + 1 )

(Tan^-1 p - Tan^-1q ) + ( Tan^-1 q - Tan^-1r ) + ( Tan^-1r - Tan^-1p ) = 0

Hence simplified


★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★