Question

•prove that.
$\frac{1}{ \sec(\pi) - \tan(\pi) } = \sec(\pi) + \tan(\pi)$
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Answer 1

its simple we have to multiply and divide with secteta + tan teta

Answer 2

[tex]Hi \: friend \: here \: is \: your \: answer. \\ \frac{1}{sec\pi - tan\pi} = sec\pi + tan\pi \\ \blue{lhs = \frac{1}{sec\pi - tan\pi} } \\ \blue{lhs = \frac{1}{sec\pi - tan\pi}} \times \frac{sec\pi + tan\pi}{sec\pi + tan\pi} \\ lhs = \frac{sec\pi + tan\pi}{ {sec}^{2} \pi - {tan}^{2} \pi} \\

Hope my answer will be help you.