Question

prove that
$sec {}^{2} θ - 1 - \tan {}^{2} θ = 0$
please help.​

Answer 1

Answer:

bracket

$( {sec}^{2} θ - 1) - {tan}^{2} θ = 0 \\ since \: {tan}^{2} θ = {sec}^{2} - 1 \\ {tan}^{2} θ - {tan}^{2} θ = 0 \\ lhs = rhs$

Step-by-step explanation:

hope it helps you<3

Answer 2

Answer:

answer is 199₹ is

Step-by-step explanation:

because I don't know