Question

Prove That :-

$\sqrt{ \frac{1 - \cos(a) }{1 + \cos(a) } } = \frac{ \sin(a) }{1 + \cos(a) }$
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Answer 1

Your Answer is in the Attachment....

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Answer 2

Answer:

• Question

Prove it

$\frac{sin \: a + cos \: a}{sina \: - cos \: a} = \sqrt{ \frac{1 + sin2a}{1 - sin2a} }$

$\bold{\underline \red{Answer-}} </p><p>$

LHS = Prove it

$\frac{sin \: a + cos \: a}{sina \: - cos \: a} </p><p>$

$\begin{gathered}= > \sqrt \green{ \frac{(sin \: a \: + cos \: a) {}^{2} }{(sin \: a \: - cos \: a) {}^{2} } } \\ \\ \\ \\ = > \sqrt \pink{ \frac{ {sin}^{2} a + {cos}^{2} a + 2sin \: a \: cosa}{ {sin}^{2} a + {cos}^{2}a - 2sin \: a \: cosa } } \\ \\ \\ \\ = > \sqrt \blue{ \frac{1 + sin2a}{1 - sin2a} }\end{gathered} </p><p>$

Hence, Proved