Prove that is an irrational number given that p and q are primes.
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√p +√q is a rational
√p +√q =a where a is a rational number
√q=a-√p
squaring both sides
q=a^2+p-2√pa
2√pa=a^2+p-q
√p=a^2+p-q/2a
which is a contradiction as right hand side is rational but left hand side is irrationa;
√p +√q =a where a is a rational number
√q=a-√p
squaring both sides
q=a^2+p-2√pa
2√pa=a^2+p-q
√p=a^2+p-q/2a
which is a contradiction as right hand side is rational but left hand side is irrationa;
Answered by
2
Heya....
====== Answer =======
√p + √q is natural no
√p+√q = a , a is rational no
√q = a-√p
Squaring both the sides ,,
q = q^2+p-2√pa
2√pa = q^2 + pq
In this, there is a contradiction , left side is rational,,
And....
Right side is irrational ....
Thank you
====== Answer =======
√p + √q is natural no
√p+√q = a , a is rational no
√q = a-√p
Squaring both the sides ,,
q = q^2+p-2√pa
2√pa = q^2 + pq
In this, there is a contradiction , left side is rational,,
And....
Right side is irrational ....
Thank you
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