Prove that
+ is an irrational, where p, q are primes.
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Answered by
0
Answer:
Let us suppose that √(p + √q) is rational.
Let √(p + √q) = a, where a is rational.
=> √q = a – √p
Squaring on both sides, we get
q = a^2 + p - 2a√p
=> √p = (a^2 + p - q)/2a, which is a contradiction as the right hand side is rational number, while√p is irrational.
Hence, √(p + √q) is irrational.
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Answered by
1
Answer:
its simple, see down
Step-by-step explanation:
sq root of a prime no is always irrational.
Sum of 2 irrational nos is also irrational
Hence proved.
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