Prove that the angle between two tangent drawn from external point is supplementary to the angle sub tended by the line segment joining the point of contact at the centre
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Given:
A circle with Centre O.AP and B P are tangents to the circle.
To prove :
<AOB+<APB=180°
Proof:
<OAP=90°
<OBP=90°
{ radius is perpendicular to the tangent}
In quadrilateral AOBP by angle sum property,
<OAP +<OBP +<AOB +<APB=360°
90°+90° +<AOB+<APB=360°
Therefore,
<AOB +<APB=360°-180°
=180°.
A circle with Centre O.AP and B P are tangents to the circle.
To prove :
<AOB+<APB=180°
Proof:
<OAP=90°
<OBP=90°
{ radius is perpendicular to the tangent}
In quadrilateral AOBP by angle sum property,
<OAP +<OBP +<AOB +<APB=360°
90°+90° +<AOB+<APB=360°
Therefore,
<AOB +<APB=360°-180°
=180°.
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