Prove that the angle opposite of equal side of equilateral triangle are equal
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Answered by
74
Step-by-step explanation:
In triangel ABD and ACD
angle A =angleA(AD is bisector of angleA)
AD=AD(common)
angle D=angleD(AD perpendicular BC)
By ASA condtion ABD congruent to ACD
By CPCT angle B=angleC
Hence proved!
Answered by
21
Answer:
Step-by-step explanation:
Step-by-step explanation:
In triangel ABD and ACD
angle A =angleA(AD is bisector of angleA)
AD=AD(common)
angle D=angleD(AD perpendicular BC)
By ASA condtion ABD congruent to ACD
By CPCT angle B=angleC
Hence proved!
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