prove that the angle which a chord makes with tangent at the point of contact are equal to that made in alternate segment
Answers
Answer:
Step-by-step explanation:
Proof: In the figure, ( radius is perpendicular to the tangent at the point of contact)
(1)
In DEAB
(Angle in a semi-circle)
(2)
From (1) and (2)
But, (Angles in the same segment)
Now, consider cyclic quadrilateral ACBD.
(Opposite angles) .(4)
And (Linear pair)
But
(5)
From (4) and (5)
Hence proved.
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