prove that the area of a triangle is half the product of any its sides and the corresponding altitudes
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Answered by
69
Heya,
Answer to your question is:-
CONSTRUCTION:
Through C and A draw CP parallel to BA and AP parallel to BC, intersecting each other at P.
PROOF:
CP parallel to BA (By Construction)
AP parallel to BC (By Construction)
Therefore BCPA is a parallelogram.
Hence AC is a diagonal of parallelogram BCPA.
Therefore,
area of triangle = ½ ar(IIgm BCPA) = ½ × BC × AD (As BC is the base and AD is the altitude of IIgm BCPA).
Hence, Proved!
HOPE THIS HELPS YOU:-))
@Ashu
Answer to your question is:-
CONSTRUCTION:
Through C and A draw CP parallel to BA and AP parallel to BC, intersecting each other at P.
PROOF:
CP parallel to BA (By Construction)
AP parallel to BC (By Construction)
Therefore BCPA is a parallelogram.
Hence AC is a diagonal of parallelogram BCPA.
Therefore,
area of triangle = ½ ar(IIgm BCPA) = ½ × BC × AD (As BC is the base and AD is the altitude of IIgm BCPA).
Hence, Proved!
HOPE THIS HELPS YOU:-))
@Ashu
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19
....HOPE IT WILL HELP YOU....
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