Question

Prove that the area of a triangle with vertices (t, t2) , (t+2, t+2) and (t+3, t) is independent of t.

Answer 1

Answer:

Step-by-step explanation:

the points are (t,t2) , (t+2 , t+2) and (t+3,t)

the formula = 1/2{x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}

                    = 1/2{t(t+2-t)+(t+2)(t-2t)+(t+3)(2t-t-2)

                     = 1/2(2t-t²+t²-2t-6)

                      = 6/2

                      = 3

Answer 2

Answer:

3 is answer dear friend