Question

prove that the area of an equilateral triangle described on one side of a square is equal to half the area of the equilateral triangle described on one of its diagonals​

Answer 1

Step-by-step explanation:

given:a square ABCD equilateral trianges BCE

and ACF have been drawn on side BC and diagonals respectively

• to prove:ar(trngl BCE)=1/2(ar trngl ACF)
• proof: trngl BCE SIMILAR trngl ACF (bcoz all equilateral trngles are equal)

area(BCE)/AREA(ACF)=bc2/ac2

=bc2/underroot bc2

(bcoz diagonal =underroot 2)

therefore

ar(BCE)/ar(ACF) = 1/2

...i tried....

....dark lover.......

Answer 2

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