PROVE THAT THE AREA OF AN EQUILATERAL TRIANGLE DESCRIBED ON SIDE OF THE SQUARE EQUAL TO THE HALF OF THE AREA OF EQUILATERAL TRINGLE DESCRIBED ON ONE OF ITS DIAGNOLS
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Listen bro this is an NCERT question of chapter triangles last question. You could refer it. At this moment you simply have a healthy also so that you can crack the paper tomorrow. All the best bhai
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Let the side of the square be 'a' then area of equilateral triangle describe on its side will be √3/4a^2=b(say),
Length of the diagonal of the square will be √2a(by Pythagoras)
now the area of equilateral triangle describe on its diagonal will be √3/4(√2a)^2=2√3/4a^2=b/2. Hence proved.
Thank you for reading.
Length of the diagonal of the square will be √2a(by Pythagoras)
now the area of equilateral triangle describe on its diagonal will be √3/4(√2a)^2=2√3/4a^2=b/2. Hence proved.
Thank you for reading.
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