If sin A =1/3,evaluate cos A cosec A +Tan A Sec A
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Answered by
21
HEY.......
HERE IS U R ANSWER
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SIN A = 1/3
= P/H
B= √H^2 - P^2
B = √ 9 - 1 =√8 = 2√2
COS A = 2√2 / 3
COSEC A = 3
TAN A = 1/2√2
SEC A = 3/ 2√2
COS A COSEC A + TAN A SECA
2√2/3 * 3 + 1/ 2√2 * 3/ 2√2
2√2 + 3 / 8
16√2 + 3 / 8
===================================
HOPE IT WILL HELP YOU A LOT....
THANKU.....
HERE IS U R ANSWER
===================================
SIN A = 1/3
= P/H
B= √H^2 - P^2
B = √ 9 - 1 =√8 = 2√2
COS A = 2√2 / 3
COSEC A = 3
TAN A = 1/2√2
SEC A = 3/ 2√2
COS A COSEC A + TAN A SECA
2√2/3 * 3 + 1/ 2√2 * 3/ 2√2
2√2 + 3 / 8
16√2 + 3 / 8
===================================
HOPE IT WILL HELP YOU A LOT....
THANKU.....
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