If sin (A+B)=1 and cos (A-B)=underroot 3 over 2. find A and B
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Answered by
2
sin(A+B)=1
(A+B)=90...(1)
cos(A-B)=√3/2
(A-B)=30...(2)
Add 1 and 2
2A=120
A=60
B=30
(A+B)=90...(1)
cos(A-B)=√3/2
(A-B)=30...(2)
Add 1 and 2
2A=120
A=60
B=30
Akashkhaira:
thanks
Answered by
1
Hey... I think this can be ur answer!!
Sin(A+B) = 1
Sin (A+B) =sin90
A+B=90
Cos (A-B) =root3/2
Cos (A-B) =30
A-B=30
Now,
Adding both
2A=120
A=60
B=30
HOPE IT HELPS YOU ☺️☺️☺️
Sin(A+B) = 1
Sin (A+B) =sin90
A+B=90
Cos (A-B) =root3/2
Cos (A-B) =30
A-B=30
Now,
Adding both
2A=120
A=60
B=30
HOPE IT HELPS YOU ☺️☺️☺️
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