Question

Prove that the bisector of any two consecutive angles of parallelogram intersect at right angle

Answer 1

Take three angles A, B, C NOW A+B=180
Therefore A÷2+B÷2 =180÷2
=angle bisector of A+angle bisector of B =90 now using the angle sum property of triangle the third angle which is formed by the meeting the angle bisectors OF A And B =90degree

Answer 2

Answer:

Step-by-step explanation:

∠A +∠B = 180° {adjacent angles are supplementary}

1/2 ∠A + 1/2∠B + ∠AOB = 180° {angle sum property}

1/2(∠A+∠B)+ ∠AOB = 180°

1/2 (180) + ∠AOB = 180°

90° + ∠AOB = 180°

∠AOB = 180-90

∠AOB = 90°