Question

Prove that the bisector of any two consecutive angles of parallelogram intersect at right angle

Answer 1

hey the answer is. . .

Answer 2

Answer:

Step-by-step explanation:

Given: Fig is a //gm

To prove: ∠AOB = 90°

Proof: ∠A +∠B = 180° {adjacent ∠ are supplementary}

         1/2 ∠A + 1/2∠B + ∠AOB = 180° {∠ sum prop.}

         1/2(∠A+∠B)+ ∠AOB = 180°

        1/2 (180) + ∠AOB = 180°

          90° + ∠AOB = 180°

          ∠AOB = 180-90

            ∠AOB = 90°

       Hence proved