Prove that the bisectors of the angles of a linear pair are at right angles
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Angles ACD and DCB are a linear pair.
Sum of these angles = 180 deg
ACD + DCB = 180 deg
CE is is bisector of angle ACD
CF is bisector of angle DCB.
RTP:- Angle ECF = 90 deg.
ECF = ECD + DCF = 1/2 ACC + 1/2 DCB = @/2 { angle ACD + angle DCB } =
1/2 180 deg = 90 deg
Hope this helps you friend
Thanks ✌️✌️
Sum of these angles = 180 deg
ACD + DCB = 180 deg
CE is is bisector of angle ACD
CF is bisector of angle DCB.
RTP:- Angle ECF = 90 deg.
ECF = ECD + DCF = 1/2 ACC + 1/2 DCB = @/2 { angle ACD + angle DCB } =
1/2 180 deg = 90 deg
Hope this helps you friend
Thanks ✌️✌️
Answered by
1
hope it's help you.....
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