prove that the bisectors of the base angles of an isosceles triangle terminated by the opposite sides are equal .
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Here ABC is an isocelous triangle with angle A= angle BMC and NB are the angle bisectorsSo now we observe triangle (MBC) and triangle(NBC)
1) BC = BC2) ang(MBC) = ang(NCB)3) ang(NBC) = ang(MCB)
so by ASA congruency condition the triangles are congruentand henceBN = CM
1) BC = BC2) ang(MBC) = ang(NCB)3) ang(NBC) = ang(MCB)
so by ASA congruency condition the triangles are congruentand henceBN = CM
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prove prove that the bisector of the base angles of an isosceles triangle are equal
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