prove that the cube root of 3 is irrational..
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Prove that the cube root of 3 is irrational:
In this, we need to prove that ∛3 is a irrational number. so, we need to assume that ∛3 is rational number.
The rational number is written as p/q where p and q are integers. q ≠ 0.
∛3 = p/q → (equation 1)
When equation (1) is cubed, then
3 = p³/q³
∴ 3q³ = p³
p³ is a perfect cube and 3q³ must also be perfect cube.
In 3q³ then q is a perfect cube whereas 4 is not a perfect cube.
Hence, the assumption is wrong. So, ∛3 is cannot be written as p/q.
Thus, ∛3 is a irrational number.
Hence proved.
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We nned to probe this by contradiction.
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