prove that the diagonal of asquare are equal and perpendicular to each other
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(draw a square ABCD with diaagonals AC and BD)
Given:ABCD is a square
To prove:AC=BD and AC and BD bisect each other at right. angles
Proof:In triangle ACB and triangle BAD
AB=AB (common side)
angle ABC=angle BAD(=90degree)
BC=AD(opposite sides of a square)
Triangle ACB congruent BAD(SAS criteria)
AC=BD by(CPCT)
in triangle OAD and OBC
angle OAB=OCB(AC transversal)
AD=CB(opposite sides of square)
angle ODA=OBC(BD transversal)
OA=OC........
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by this process we get the answer
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