prove that the diagonal of rectangle divide into two congruent triangle
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if abcd is a rectangle and bd is a diagonal.
in triangles abd and cdb :
=) ab = cd
=) bd = bd
ad = cb
by sss congruency criteria ;
both are congruent.
in triangles abd and cdb :
=) ab = cd
=) bd = bd
ad = cb
by sss congruency criteria ;
both are congruent.
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Answered by
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Given:ABCD is a rectangle
AC is the diagonal of the rectangle
RTP:∆ABC congruent to ∆ADC
Proof:
=>AB=DC(Opposite sides of a rectangle are equal)
=>AD=BC(Opposite sides of a rectangle are equal)
=>AC=AC(Common side)
Hence ∆ABC is congruent to ∆ADC(By SSS congruence rule)
AC is the diagonal of the rectangle
RTP:∆ABC congruent to ∆ADC
Proof:
=>AB=DC(Opposite sides of a rectangle are equal)
=>AD=BC(Opposite sides of a rectangle are equal)
=>AC=AC(Common side)
Hence ∆ABC is congruent to ∆ADC(By SSS congruence rule)
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