Prove that the diagonal of the rectangle are equal
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Given :-
Let ABCD is rectangle with diagonals AC & BD
To Prove :-
We have to prove that AC = BD
Proof :-
Let ABCD be a rectangle
In ∆ABC and ∆ADC
AC = AC (Common)
AD = BC ( Opposite sides of parallelogram, a rectangle is a parallelogram)
∠ABC = ∠ADC = 90° (All angles of rectangle are 90°)
So, By SAS congruency rule of triangles
∆ABC and ∆ADC are congruent to each other
Hence, AC = AB (Corresponding part of congruent triangle)
Hence proved ✔
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