prove that the diagonals of a rectangle divide it in two congruent triangle
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A rectangle is a quadrilateral whose interior angles are all equal.
✔️Properties of a rectangle :-
Property 1. Each of the interior angles of a rectangle is 90°.
Property 2. The diagonals of a rectangle bisect each other.
Property 3. The opposite sides of a rectangle are parallel.
Property 4. The opposite sides of a rectangle are equal.
✔️Proof:-
in rectangle ABDC
AD and CB are diagonals.
in ∆ABD and ∆DCA
➖AB=DC ( opposite sides of rectangle )
➖BD=CA ( opposite sides of rectangle )
➖AD=DA ( common )
so therefore,
∆ABD is congruent to ∆DCA by SSS congruency.....
✔️Properties of a rectangle :-
Property 1. Each of the interior angles of a rectangle is 90°.
Property 2. The diagonals of a rectangle bisect each other.
Property 3. The opposite sides of a rectangle are parallel.
Property 4. The opposite sides of a rectangle are equal.
✔️Proof:-
in rectangle ABDC
AD and CB are diagonals.
in ∆ABD and ∆DCA
➖AB=DC ( opposite sides of rectangle )
➖BD=CA ( opposite sides of rectangle )
➖AD=DA ( common )
so therefore,
∆ABD is congruent to ∆DCA by SSS congruency.....
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